Construct a triangle $PQR$ in which $QR = 6 cm$ , $∠ Q = 60 °$ and $PR - PQ = 2 cm$ .

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Solution

Draw a line segment of base $QR = 6 cm$ . Measure and draw $∠ Q = 60 °$ and let the ray be $QX$ .
Open a compass and measure $PR - PQ = 2 cm$ .
As $P Q - P R$ is negative, $QD$ will be below the line $QR$ .
With $Q$ as a centre, draw an arc on the ray $QX$ . Let the arc intersect $QX$ at the point $D$ . Join $RD$ .
Draw the perpendicular bisector of the line $RD$ and the intersection point is taken as $P$ . Join $PR$ .
Hence, $PQR$ is the required triangle.

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