Deduce The Structure Of Brf5 On The Basis Of Vsepr Theory

Valence electrons in \(BrF_{5}\) is 7 + 5 × 7 = 42.

The distribution of these electrons in BrF5 is explained below in the diagram

distribution of these electrons in BrF5

 

BrF5

 

There are six lone pairs of electrons around Br. Hence, the arrangement of these electrons around Br will be octahedral.

The hybridization involved is \(sp^{3}d^{2}\)

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question