Question

Divide the given polynomial by the given monomial: $(3y^8-4y^6+5y^4)÷y^4$

Answer 1

Here ,

We will divide a polynomial by monomial

$$\begin{gathered} =\frac{(3y^8-4y^6+5y^4)}{y^4} \\ =\frac{3y^8}{y^4}-\frac{4y^6}{y^4}+\frac{5y^4}{y^4} \\ =\mathbf{3}{\mathit{y}}^{\mathbf{4}}\mathbf{-}\mathbf{4}{\mathit{y}}^{\mathbf{2}}\mathbf{+}\mathbf{5} \end{gathered}$$

Thus,

$(3y^8-4y^6+5y^4)÷y^4$ $=\mathbf{3}{\mathit{y}}^{\mathbf{4}}\mathbf{-}\mathbf{4}{\mathit{y}}^{\mathbf{2}}\mathbf{+}\mathbf{5}$