Question

Draw $\angle POQ$ of measure $75°$ and find its line of symmetry.

Answer 1

Step 1. Draw $\angle POQ$ of measure $75°$.

Draw a ray $\mathrm{OQ}$:

Place the center of the protractor at $\mathrm{O}$ and the zero edge along $\mathrm{OQ}$:

Mark point $\mathrm{P}$ on $75°$ and then join $\mathrm{OP}$:

Step 2. Draw the axis of symmetry.

Mark points $\mathrm{C}$ and $\mathrm{D}$ where the arc intersects $\mathrm{OQ}$ and $\mathrm{OP}$:

Taking $\mathrm{C}$ and $\mathrm{D}$ as centers and with the radius more than $\frac{1}{2}\mathrm{CD}$, draw arcs to intersects each other and then join $\mathrm{O}$ and $\mathrm{E}$.

Hence, $\mathrm{OE}$ is the line of symmetry of $\angle \mathrm{POQ}=75°$.