Question

Draw the following: A parallelogram $\mathrm{OKAY}$ where $\mathrm{OK}=5.5\mathrm{cm}$ and $\mathrm{KA}=4.2\mathrm{cm}$.

Answer 1

Step 1. Draw a parallelogram $\mathrm{OKAY}$ where $\mathrm{OK}=5.5\mathrm{cm}$ and $\mathrm{KA}=4.2\mathrm{cm}$.

In parallelogram, opposite sides are equal.

$$\begin{gathered} \mathrm{YA}=\mathrm{OK}=5.5\mathrm{cm} \\ \mathrm{YO}=\mathrm{KA}=4.2\mathrm{cm} \end{gathered}$$

Draw side $\mathrm{OK}$ of length $5.5\mathrm{cm}$:

Draw $90°$ from point $\mathrm{O}$:

Draw $90°$ from point $\mathrm{K}$:

.

Taking $4.2\mathrm{cm}$ as radius, and $\mathrm{O}$ as center and then draw an arc and Mark the point where arc and line intersect as $\mathrm{Y}$:

Taking $4.2\mathrm{cm}$ as radius, and $\mathrm{K}$ as center and then draw an arc and Mark the point where arc and line intersect as $\mathrm{A}$:

Join $\mathrm{YA}$ and label the sides:

Hence, a parallelogram $\mathrm{OKAY}$ is formed where $\mathrm{OK}=5.5\mathrm{cm}$ and $\mathrm{KA}=4.2\mathrm{cm}$.