Drive an expression for the magnetic moment of an electron revolving around the nucleus in term of its angular momentum what is the direction of magnetic moment of the electron with respect to its angular momentum

We know that, \(\mu = iA\frac{ev}{2\pi r}\times \pi r^{2}=\frac{evr}{2}\)

As l = mvr

\(vr= \frac{1}{m}\)

\(\underset{\mu }{\rightarrow}=-\frac{e\underset{l}{\rightarrow}}{2m}\)

Therefore, it can be said that the direction of mu is always opposite to that of the direction of l.

Also, it is positive when the movement is anticlockwise and negative when the movement is clockwise.

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