Question

Element A has 3 electrons in the outermost orbit and element B has 6 electrons in the outermost orbit. The formula of the compound formed A and B would be:

• A. A₂B
• B. A₂B₂
• C. A₂B₃
• D. A₃B₆

Answer 1

The correct option is C

A₂B₃

Explanation

• In a neutral molecule, the sum of the bonding valance electrons must be equal.
• So the products of the positive element and its charge and the negative element and its charges must be equal.

The explanation for the correct answer

If there are three valance electrons, then the charge on A will either be$+3or-5$ for a full octet and the valance electron in ‘B’ atoms will mainly result in an acquisition of additional electrons $2$ for an octet and relative charge of $-2$.

Now by balancing the two, we get

$$\begin{gathered} \mathrm{A}:\mathrm{B} \\ \swarrow \searrow \\ 32 \\ \mathrm{Therefore}{\mathrm{A}}_2{\mathrm{B}}_3 \end{gathered}$$

Element A has 3 electrons in the outermost orbit and element B has 6 electrons in the outermost orbit. The formula of the compound formed A and B would be${\mathrm{A}}_2{\mathrm{B}}_3$.

Therefore Option C is the correct option.