Evaluate (102)³3 (3 is power ) using suitable identities.

Answer:

(102 )³ can be written as (100 + 2)³

Using identity here ;

( a + b )³ = a³ + b³ + 3ab ( a + b )

⇒ (100 + 2)³

⇒ (100)³ + (2)³ + 3 × 100 × 2 (100 + 2)

⇒ 1000000 + 8 + 600 ( 102 )

⇒ 1000000 + 8 + 61200

⇒ 1061208

Therefore the answer is 1061208.