Evaluate 103×97 by using identities
Given expression
103×97=(100+3)(100-3)
We know that
(a+b)(a-b)=a2-b2
Using it
⇒(100+3)(100-3)=1002-32=10000-9=9991
Hence the result is 9991
Question 86 (x)
Using suitable identities, evaluate the following:
104×97
98×103