Expand (2x+3y)2.
Expansion of (2x+3y)2.
We use the identity (a+b)2=a2+2ab+b2
So, here a=2xandb=3y
⇒(2x+3y)2=(2x)2+2×2x×3y+(3y)2=4x2+12xy+9y2
Hence, expansion of (2x+3y)2is 4x2+12xy+9y2.
Factorise:12(2x−3y)2−16(3y−2x)
Factorise : 1−(2x+3y)−6(2x+3y)2