Given expression: (x – 1)3
Using the algebraic identity: (a – b)3 = a3 – b3 – 3ab(a – b)
(x – 1)3 = x3 – 13 – 3(x)(1)(x – 1)
= x3 – 1 – 3x(x – 1)
= x3 – 1 – 3x2 + 3x
Therefore, (x – 1)3 = x3 – 3x2 + 3x – 1.
Given expression: (x – 1)3
Using the algebraic identity: (a – b)3 = a3 – b3 – 3ab(a – b)
(x – 1)3 = x3 – 13 – 3(x)(1)(x – 1)
= x3 – 1 – 3x(x – 1)
= x3 – 1 – 3x2 + 3x
Therefore, (x – 1)3 = x3 – 3x2 + 3x – 1.
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