Explain the heating effect of electric current

HEATING EFFECT OF ELECTRIC CURRENT: The phenomenon when a steady current flows through conductor the energy liberated during the current flow exhibited as heat

Consider a conductor of AB having potential difference V, potential at A is Va and potential at B is VB

If VA > VB

The potential energy of an electron at A is

UA = – q VA


Potential energy of an electron at B is

UB = – q VB

If current flow through the conductor is (i) then amount of charge flows through the conductor in dt time is

dq = i dt

Number of electron flowing from end B to A in dt time is


When electron moves from lower potential to higher potential there will be energy loss of electron (i.e., loss in potential energy)

\(dw=\left( \frac{Idt}{e} \right)\left[ \left( -e{{V}_{B}} \right)-\left( -e{{V}_{A}} \right) \right]\) \(=\frac{Idt\,\,e}{e}\left( {{V}_{A}}-{{V}_{B}} \right)\) \(dw=I\,dt\,v\) \(dw=V\,I\,dt\) ….. (1)

Electrical power (p) is defined as


P = V I ….. (2)

V = I R

P = V I = I2R

In general if electric current flows for a time t, the energy liberated will be

\(H=\frac{w}{J}\) \(J=4.2\,\,J/cal\) \(H=\frac{w}{4.2}=\frac{VIt\,}{4.2}\) \(H=\frac{{{I}^{2}}Rt}{4.2}\)


When a steady current (i) flows for time (t) through a conductor by a source of emf E. then amount of charge that flow through conductor in time (t) is

Q = I t

Electrical energy delivered to charge flow through the conductor is

W = Q V = V I t

Thus, electric power given to the circuit is

\(P=\frac{W}{t}=\frac{VIt}{t}=VI\) \(P=VI={{I}^{2}}R\)

Let as consider a simple circuit:

In the given circuit.

The rate at which chemical energy is converted into electrical energy is EI and power delivered across the external resistor R is I2R and power dissipated across the internal resistance of the cell is i2r, it can written as



When a steady current flows through conductor, heat is produced in it. This is known as Joule’s Heating effect the heat developed across the external load resistance is given by

H = I2Rt

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