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Question

Explain the procedure to find dy2dx2 [second order derivative] of any function y=f(x).


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Solution

Definition

  • Double derivative or dy2dx2 is defined as derivative of dydx .

Example

Let the function be f(x)=y=x2+x .

  • Now, the first derivative is -

dydx=d(x2+x)dxdydx=2x+1 (differentiating y with respect to x)

  • Now, second derivative is -

dy2dx2=d(2x+1)dxdy2dx2=2 (differentiating dydx with respect to x)

Hence dy2dx2 of f(x) is 2 .


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