Factorize ab(x2+y2)−xy(a2+b2)
Find Factors of abx2+y2-xya2+b2
Simplify the function by taking bx,ay common.
abx2-xyb2+aby2-xya2=bxax-yb-ayax-by
=bx-ayax-by
Hence the answer is bx-ayax-by
Factorise :
(i) a2−ab−3a+3b(ii) x2y−xy2+5x−5y(iii) a2−ab(1−b)−b3(iv) xy2+(x−1)y−1(v) (ax+by)2+(bx−ay)2(vi) ab(x2+y2)−xy(a2+b2)(vii) m−1−(m−1)2+am−a
Factorise: ab(x2+1)+x(a2+b2)