Factorise the following expression: a4-b4
Factorise by using identities
Given, a4-b4
We know that a2-b2=(a-b)(a+b)
Now, upon comparing a4-b4 with this identity, we get
=(a2)2-(b2)2=(a2-b2)(a2+b2)=(a-b)(a+b)(a2+b2)
Therefore, a4-b4 can be factorised as (a-b)(a+b)(a2+b2).
Factorise Completely : a4−b4
Question 92 (xviii)
Factorise the following using the identity a2−b2=(a+b)(a−b).
a4−(a−b)4