Factorise the following expression- am-2 - bm-2 - bn-2 - an-2 - Maths Q-A

Factorise by separating the like term(s)Given, am^2+bm^2+bn^2+an^2=m^2(a+b)+n^2(a+b)0ex0ex=(a+b)(m^2+n^2) Therefore, the factorisation of am^2+bm^2+bn^2+an^2 wi ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

GCD of Polynomials

Factorise the...

Question

Factorise the following expression: $a m^{2} + b m^{2} + b n^{2} + a n^{2}$

Open in App

Solution

Factorise by separating the like term(s)
Given, $a m^{2} + b m^{2} + b n^{2} + a n^{2}$
$= m^{2} (a + b) + n^{2} (a + b) = (a + b) (m^{2} + n^{2})$
Therefore, the factorisation of $a m^{2} + b m^{2} + b n^{2} + a n^{2}$ will be $(a + b) (m^{2} + n^{2})$ .

Suggest Corrections

Similar questions

Q. Question 3(iv)
Factorise the expressions

a m^{2} + b m^{2} + b n^{2} + a n^{2}

Q. Factorise the expression
(i)

a x^{2} + b x

(ii)

7 p^{2} + 21 q^{2}

(iii)

2 x^{3} + 2 x y^{2} + 2 x z^{2}

(iv)

a m^{2} + b m^{2} + b n^{2} + a n^{2}

(v)

(l m + l) + m + 1

(vi)

y (y + z) + 9 (y + z)

(vii)

5 y^{2} - 20 y - 8 z + 2 y z

(viii)

10 a b + 4 a + 5 b + 2

(ix)

6 x y - 4 y + 6 - 9 x

Q. The perimeters of a square and a rectangle are equal. If their areas be A m² and B m², then which of the following is a true statement?

(a) A < B
(b) A ≤ B
(c) A > B
(d) A ≥ B

Q. ABCD is a rectangle. Points M and N are on BD such that AM ⊥ BD and CN ⊥ BD. Prove that BM² + BN²= DM²+ DN².

Factorise the expression.

a m^{2} + b m^{2} + b n^{2} + a n^{2}

Join BYJU'S Learning Program

Factorise the following expression: am2+bm2+bn2+an2

Factorise by separating the like term(s)Given, am2+bm2+bn2+an2=m2(a+b)+n2(a+b)=(a+b)(m2+n2) Therefore, the factorisation of am2+bm2+bn2+an2 will be (a+b)(m2+n2).

Factorise the following expression: $a m^{2} + b m^{2} + b n^{2} + a n^{2}$

Factorise by separating the like term(s)
Given, $a m^{2} + b m^{2} + b n^{2} + a n^{2}$
$= m^{2} (a + b) + n^{2} (a + b) = (a + b) (m^{2} + n^{2})$
Therefore, the factorisation of $a m^{2} + b m^{2} + b n^{2} + a n^{2}$ will be $(a + b) (m^{2} + n^{2})$ .