Factorize the following expression: x4-(x-z)4.
Factorizex4-(x-z)4.
The given expression can be written as
x4-(x-z)4=x22-((x-z)2)2
=x2+x-z2x2-x-z2 {∴a2-b2=(a+b)(a-b)}
=x2+x2-2xz+z2x2-x2+2xz-z2=2x2-2xz+z22xz-z2=2x2-2xz+z22x-zz
Hence the factorized form isz(2x-z)(2x2-2xz+z2).