Factorise- x-2 - xy - 8x - 8y - Maths Q-A

We need to factorise x^2+xy+8x+8y:x^2+xy+8x+8y0ex0ex=x^2+8x+xy+8y0ex0ex=x(x+8)+y(x+8)0ex0ex=(x+8)(x+y)Therefore, the factors of x^2+xy+8x+8y are (x+8) and (x+y) ...

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Standard VIII

Mathematics

Prime Factorisation

Factorise: x^...

Question

Factorise: $x^{2} + x y + 8 x + 8 y$

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Solution

We need to factorise $x^{2} + x y + 8 x + 8 y$ :
$x^{2} + x y + 8 x + 8 y = x^{2} + 8 x + x y + 8 y = x (x + 8) + y (x + 8) = (x + 8) (x + y)$
Therefore, the factors of $x^{2} + x y + 8 x + 8 y$ are $(x + 8)$ and $(x + y)$ .

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Q. Question 3(i)
Factorise

x^{2} + x y + 8 x + 8 y

Q. The equation of the parabola with focus (0, 0) and directrix x + y = 4 is
(a) x² + y² − 2xy + 8x + 8y − 16 = 0
(b) x² + y² − 2xy + 8x + 8y = 0
(c) x² + y² + 8x + 8y − 16 = 0
(d) x² − y² + 8x + 8y − 16 = 0

Q. Factorise:

x^{2} + x y + 8 x + 8 y

Factorise the following expression:

x^{2} + x y + 8 x + 8 y

Q. Question 3(i)
Factorise

x^{2} + x y + 8 x + 8 y

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Factorise: x2+xy+8x+8y

We need to factorise x2+xy+8x+8y:x2+xy+8x+8y=x2+8x+xy+8y=x(x+8)+y(x+8)=(x+8)(x+y)Therefore, the factors of x2+xy+8x+8y are (x+8) and (x+y).

Factorise: $x^{2} + x y + 8 x + 8 y$

We need to factorise $x^{2} + x y + 8 x + 8 y$ :
$x^{2} + x y + 8 x + 8 y = x^{2} + 8 x + x y + 8 y = x (x + 8) + y (x + 8) = (x + 8) (x + y)$
Therefore, the factors of $x^{2} + x y + 8 x + 8 y$ are $(x + 8)$ and $(x + y)$ .