Factorise - x-3 - 6x-2 - 11x - 6 using Factor theorem- - Maths Q-A

Factorize the polynomial:Given: x^3+x 3x^2 3x^3+x 3x^2 30ex0ex=x(x^2+1) 3(x^2+1)=(x 3)(x^2+1)Hence, the factorized form of x^3+x 3x^2 3 is (x 3)(x^2+1). ...

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Standard X

Mathematics

Factorisation of Trinomials by Splitting Middle Term

Factorise : x...

Question

Factorize: $x^{3} + x - 3 x^{2} - 3$ .

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Solution

Factorize the polynomial:
Given: $x^{3} + x - 3 x^{2} - 3$
$x^{3} + x - 3 x^{2} - 3 = x (x^{2} + 1) - 3 (x^{2} + 1)$
$= (x - 3) (x^{2} + 1)$
Hence, the factorized form of $x^{3} + x - 3 x^{2} - 3$ is $(x - 3) (x^{2} + 1)$ .

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Factorize: x3+x-3x2-3.

Factorize the polynomial:Given: x3+x-3x2-3x3+x-3x2-3=x(x2+1)-3(x2+1)=(x-3)(x2+1)Hence, the factorized form of x3+x-3x2-3 is (x-3)(x2+1).

Factorize: $x^{3} + x - 3 x^{2} - 3$ .

Factorize the polynomial:
Given: $x^{3} + x - 3 x^{2} - 3$
$x^{3} + x - 3 x^{2} - 3 = x (x^{2} + 1) - 3 (x^{2} + 1)$
$= (x - 3) (x^{2} + 1)$
Hence, the factorized form of $x^{3} + x - 3 x^{2} - 3$ is $(x - 3) (x^{2} + 1)$ .