Find 45 of 20.
Find the required value:
The required values can be calculated as,
45of20=45×20 ∵aofb=a×b
⇒45of20=41×4
⇒45of20=4×4
⇒45of20=16
Hence, 45 of 20 is 16.
The sum of the series 23!+45!+67!+... to ∞ = ae. Find (a+3)2.