Find dy/dx, If y = log (sin 3x).

y = log(sin 3x)

Differentiating with respect to x, we get,

\(\frac{dy}{dx} = \frac{1}{sin\; 3x} * 3 \;cos\; 3x\) \(\frac{dy}{dx} = \frac{3 \;cos\; 3x}{sin\; 3x}\)

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