To find the value of tan(∏/3) let us consider a right-angled triangle. We know that tan (∏/3)= 60 degrees.
The tan function of an angle is equal to the length of the opposite side divided by the length of the adjacent side.
Tan θ = opposite side/ Adjacent Side
In terms of sine and cosine function, the tangent function is represented by
Tan θ = sin θ / Cos θ
To find the value of tan 60 degrees geometrically, consider an equilateral triangle ABC since each of an angle in an equilateral triangle is 600.
Therefore, ∠A = ∠B = ∠C = 60°
Draw a perpendicular line AD from A to BC.
Now consider the triangle, ABD and ADC,
We have, ∠ ADB = ∠ADC= 90° and
∠ ABD = ∠ACD= 60°
Therefore, AD=AD
According to AAS Congruency,
Δ ABD ≅ Δ ACD
From this, we can say
BD = DC
Let us take, AB = BC =2a
Then, BD= ½ (BC) =½ (2a) =a
By using Pythagoras theorem,
AB2 = AD2– BD2
AD2= AB2-BD2
AD2 =(2a)2 – a2
AD2 = 4a2-a2
AD2 = 3a2
Therefore, AD=a√3
Now in triangle ADB,
Tan 600= AD/BD
= a√3/a = √3
Therefore, tan 60 degrees exact value is given by,
Tan 60=√3