Question

Find the oxidation number of sodium$\left(\mathrm{Na}\right)$ in$\mathrm{NaCl}$.

Answer 1

Step-1 Calculating the charge on $\mathrm{NaCl}$

• $\mathrm{NaCl}$ is an inorganic salt.
• The overall charge on $\mathrm{NaCl}$ = $0$

Step-2 Calculating the oxidation number of $\left(\mathrm{Na}\right)$ in$\mathrm{NaCl}$-:

1. As per standard, the oxidation number of Sodium$\left(\mathrm{Na}\right)$= $x$
2. The oxidation number on Chlorine $\left(Cl\right)$= $-1$

$FormalChargeonNaCl=OxidationnumberofNa+OxidationnumberofCl$

$0=x+\left(-1\right)$

$0=x-1$

$x=+1$

Hence, the oxidation number of Sodium $\left(\mathrm{Na}\right)$ in $\mathrm{NaCl}$ is $+1$