Question

Find the remainder when $x^3+3x^2+3x+1$ is divided by $x$.

Answer 1

Step 1: Determine the value of $x$ for the divisor

Given equation is $x^3+3x^2+3x+1$ which is divided by $x$.

Put divisor $x$$=0$

Step 2: Determine the Remainder

Consider the equation

$x^3+3x^2+3x+1$

Putting $x=0$

$\therefore$Remainder is

$p\left(0\right)={\left(0\right)}^3+3{\left(0\right)}^2+3\left(0\right)+1$

$=1$

Hence, remainder when $x^3+3x^2+3x+1$ is divided by $x$ is $1$.