Question

Find the roots of the following quadratic equation by factorisation: $x^2-3x-10=0$.

Answer 1

Solve for $x$:

The given equation is,

$x^2-3x-10=0$

$\Rightarrow$$x^2-5x+2x-10=0$

$\Rightarrow$$x\left(x-5\right)+2\left(x-5\right)=0$

$\Rightarrow$ $\left(x-5\right)\left(x+2\right)=0$

$\Rightarrow$$x-5=0,x+2=0$

$\therefore x=5,-2$

Hence, the roots of the given equation are $5$ and $-2$.