Find the roots of the given equation16x-10x=27
Finding the roots of given equation :
Given equation 16x-10x=27Both sides multiply by x, we get⇒16x2-10=27x⇒16x2-27x-10=0⇒16x2-(32-5)x-10=0⇒16x2-32x+5x-10=0⇒16x(x-2)+5(x-2)=0⇒(16x+5)(x-2)=0⇒x=-516,2
Hence the required roots are -516&2
Solve the following quadratic equation by factorization. 16x−10x=27