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Question

Find the sum of all natural numbers which are multiples of 7 or 3 or both and lie between200 and 500.


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Solution

Step 1: Solve for the sum of a multiple of 3 between 200 and 500

The sum is calculated in the following way.

S=S3+S7-S21where,

S3is the sum of all multiples of 3 between 200 and 500

S7is the sum of all multiples of 7 between 200 and 500

S21is the sum of all multiples of 21 between 200 and 500

S3 is an AP with first term a=201and common difference d=3and last term an=498

last term of an AP is an=a+(n-1)d

498=201+(n-1)32973=n-199=n-1n=100

Now solving further,

Sum of an AP=n2a+an

S3=1002[201+498]S3=50×699S3=34950

Step 2: Solve for the sum of a multiple of 7 between 200 and 500

Similarly, S7 and S21 is an AP having the first term a=203,210, common difference d=7,21and last term an=497,483 respectively

an for S7=203+(n-1)7

497=203+(n-1)72947=n-143=n

S7=432(203+497)S7=432×700S7=15050

Step 3: Solve for the sum of a multiple of 21 between 200 and 500

an for S21=210+(n-1)21

483=210+(n-1)2127321=n-114=n

S21=142210+483S21=7×693S21=4851

Step 4: Solve for the sum of a multiple of 3or 7 between 200 and 500

S=S3+S7-S21S=34950+15050-4851S=45149

Hence, the sum of all natural numbers which are multiples of 7 or3 or both, and lie between200 and 500 is 45149.


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