Question

Find the value of $\log \left(1\right)+\log \left(2\right)+\log \left(3\right)$

Answer 1

Find the value

$$\begin{gathered} =\log \left(1\right)+\log \left(2\right)+\log \left(3\right) \\ =\log \left(2\right)+\log \left(3\right)\left[\because \log \left(1\right)=0\right] \\ =\log \left(2·3\right)\left[\because \log \left(a\right)+\log \left(b\right)=\log \left(a·b\right)\right] \\ =\log \left(6\right)=0.778 \end{gathered}$$

Hence, the required value of $\log \left(1\right)+\log \left(2\right)+\log \left(3\right)$ is $0.778$