Question

Find two solutions the equation $(3x-2y=5)$

Answer 1

Find the solution(s) of the equation

Given, $(3x-2y=5)$

Let $x$ be equal to $1$.

Replace $x=1$ in $(3x-2y=5)$, we get

$$\begin{gathered} \Rightarrow 3\left(1\right)-2y=5 \\ \Rightarrow 3-2y=5 \\ \Rightarrow -2y=5-3 \\ \Rightarrow y=\frac{2}{-2}=-1 \end{gathered}$$

So, one solution can be $(1,-1)$.

Now assume $x$ as $2$.

Replace $x=1$ in $(3x-2y=5)$, we get

$$\begin{gathered} \Rightarrow 3\left(2\right)-2y=5 \\ \Rightarrow 6-2y=5 \\ \Rightarrow -2y=5-6 \\ \Rightarrow y=\frac{-1}{-2}=\frac{1}{2} \end{gathered}$$

So, other solution can be $(2,\frac{1}{2})$

Therefore, the two possible solutions of $(3x-2y=5)$ can be $(1,-1)$ and $(2,\frac{1}{2})$.