1.√(x+√(x+√(x…)))=y=>y^2=x+y=>
y=(1+/−√1+4x−−−−−)/2..(1),x>−1/4
2.√x(√x(√x..))=y=>y^2=x∗y=>y=x..(2)
From (1&2)=>1+1+4x−−−−−√=2x=>4×2–8x=0=>x=2||x=0.
1.√(x+√(x+√(x…)))=y=>y^2=x+y=>
y=(1+/−√1+4x−−−−−)/2..(1),x>−1/4
2.√x(√x(√x..))=y=>y^2=x∗y=>y=x..(2)
From (1&2)=>1+1+4x−−−−−√=2x=>4×2–8x=0=>x=2||x=0.
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