For a body in a circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is...... times the magnitude of its instantaneous acceleration

a) 2/π

b) π/2

c) π

d) 2

Answer: a) 2/π

Solution:

Average acceleration, a_avg = ΔV/ Δt

= 2ωR/(πR/ωR)

=2ω²R/π

Instantaneous acceleration, a_i = ω²R

(a_avg /a_i)=2/π

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