For any two non-zero rational numbers x and y- x-4 - y-4 is equal to -a- -x - y-0 -b- -x - y-1 -c- -x - y-4 -d- -x - y-8 - Maths Q-A

Explanation for the correct option:According to the law of exponents, 𝑎^𝐦÷𝑏^𝐦=(a÷b)^𝐦.∴x^4÷y^4=(x÷y)^4Hence, the correct option is option C. ...

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Standard VII

Mathematics

Quotient Law

For any two n...

Question

For any two non-zero rational numbers $x$ and $y$ , $x^{4} \div y^{4}$ is equal to:

${(x \div y)}^{0}$

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${(x \div y)}^{1}$

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${(x \div y)}^{4}$

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${(x \div y)}^{8}$

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Solution

The correct option is C
${(x \div y)}^{4}$

Explanation for the correct option:
According to the law of exponents, $a^{m} \div b^{m} = {(a \div b)}^{m}$ .
$∴ x^{4} \div y^{4} = {(x \div y)}^{4}$
Hence, the correct option is option C.

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For any two non-zero rational numbers x and y, x4÷y4is equal to:

The correct option is C x÷y4Explanation for the correct option:According to the law of exponents, am÷bm=(a÷b)m.∴x4÷y4=x÷y4Hence, the correct option is option C.

For any two non-zero rational numbers $x$ and $y$ , $x^{4} \div y^{4}$ is equal to:

The correct option is C
${(x \div y)}^{4}$

Explanation for the correct option:
According to the law of exponents, $a^{m} \div b^{m} = {(a \div b)}^{m}$ .
$∴ x^{4} \div y^{4} = {(x \div y)}^{4}$
Hence, the correct option is option C.