For how long time period should a flow of 10^19 electrons be maintained between two points A and B to have a constant current of 8 A between them?

We know that, q=ne

Also, I = q/t

Hence, t = ne/I = (1019 x 1.6 x10-19) / 8 = 0.2 s

Leave a Comment

Your email address will not be published. Required fields are marked *


Free Class