Question

For how long time should a flow of ${10}^{19}$ electrons be maintained between two points $A$ and $B$ to have a constant current of $8A$ between them?

Answer 1

Step 1: Given Data

It is given that current, $I=8A$ and number of electrons $n={10}^{19}$.

The value of $e=1.6\times {10}^{-19}C$

Step 2: Calculate the Time Period

We know that charge is given by,

$q=ne$

where, $n$ is the number of electrons, and $e$ is the charge of an electron.

Also, the current is given by,

$I=\frac{q}{t}$

where, $t$ is the time period.

Hence,

$t=\frac{ne}{I}$

$=\frac{{10}^{19}x1.6x{10}^{-19}}{8}$

$=0.2s$

Hence, the required time period is $0.2s$.