Force between two identical short bar magnets whose centres are r metre apart is 4.8 N when their axes are in the same line. If the separation is increased to 2r metre, the force between them is reduced to?


Two bar magnets placed axially at distance r

Force between them = 4.8N


Force between two magnetic dipoles is = F = μ<sub>o</sub>6M1M2/4πd<sup>4</sup>

F is inversely proportional r<sup>4</sup>

Therefore, new force = F’ = F/2<sup>4</sup> (because new d = 2r)

F’ = 4.8/16 = 0.3 N

Therefore, 3N force is reduced between the two identical short bar magnets.

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