Question

Given two points $A=\left\{2,4\right\}$ and $B=\left\{3,6\right\}$ in $2D$ plane.

Euclidean distance between the points is

Answer 1

Compute the Euclidean distance:

In the question, two points $A=\left\{2,4\right\}$ and $B=\left\{3,6\right\}$ in $2D$ plane are given.

We know that, if two points are $\left\{x_1,y_1\right\}$ and $\left\{x_2,y_2\right\}$ then the shortest distance $d$ between them is given by: $d=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$.

So, the required distance is:

$$\begin{gathered} AB=\sqrt{{(3-2)}^2+{(6-4)}^2} \\ \Rightarrow AB=\sqrt{1+4} \\ \Rightarrow AB=\sqrt{5} \end{gathered}$$

Hence the Euclidean distance is $\sqrt{5}$ units.