How can I plot root 9.3 on the number line?

Here are the stepwise explanation for the plotting of 9.3 on the number line

1. Draw a line AB by measuring 9.3cm
2. From the point, B add 1cm and mark it as C
3. Mark the point of bisection by a compass and say it as ‘O’
4. Measure AO which is the radius and draws a semi-circle.
5. From B draw a perpendicular AB touching the semi-circle and mark as D
6. Draw an arc on the number line by taking compass pointer on B and pencil on D
7. The point which intersects the number line is the square root of 9.3