How do you factor completely x³ - 1?

We have to solve x3-1

Solution

x³-1 is in the form x3 – 13

It is in the form of identity

(a³ – b³) = (a – b)(a² + b² + ab)

x³ – 1³= (x-1) (x2 +1²+ (x)(1))

x³ – 1³= (x-1) (x² +1²+ x)