# How do you find the derivative of y = 1/sqrt(x)

We have to find the derivative of 1/√x

### Solution

We can express 1/√x as x-1/2

We know that

$\frac{\mathrm{d} }{\mathrm{d} x}x^{n}=nx^{n-1}$

Using the above equation we can solve 1/√x

=$\frac{-1}{2}x^{-\frac{1}{2}-1}$

=$\frac{-1}{2}x^-\frac{3}{2}$

=$-\frac{1}{2x^{\frac{3}{2}}}$

1/√x=$-\frac{1}{2x^{\frac{3}{2}}}$