# How do you find the diagonal of a rectangle whose sides are 20 and 48?

We have to find the diagonal of a rectangle whose sides are 20 and 48.

### Solution

Let us assume that the sides of a given rectangle as

length L= 20 units

#### Formula

Diagonal of a Rectangle
$\ Diagonal\;of\;a\;Rectangle=\sqrt{l^{2}+b^{2}}$

Where,
l is the length of the rectangle.
b is the breadth of the rectangle.

Now for the given rectangle

diagonal = $\sqrt{20^{2}+ 48^{2}}$

=$\sqrt{400+ 2304}= \sqrt{2704}=52$

Hence the diagonal is 52 units for the given rectangle