How do you find the diagonal of a rectangle whose sides are 20 and 48?

We have to find the diagonal of a rectangle whose sides are 20 and 48.

Solution

Let us assume that the sides of a given rectangle as

length L= 20 units

Breadth b= 48 units

Formula

Diagonal of a Rectangle
\(\ Diagonal\;of\;a\;Rectangle=\sqrt{l^{2}+b^{2}}\)

Where,
l is the length of the rectangle.
b is the breadth of the rectangle.

Now for the given rectangle

diagonal = \(\sqrt{20^{2}+ 48^{2}}\)

=\(\sqrt{400+ 2304}= \sqrt{2704}=52\)

Hence the diagonal is 52 units for the given rectangle

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