How do you find the exact value of sin 105 degrees?

We know that sin(a+b)=sina⋅cosb+cosa⋅sinb

Therefore, sin(105)=sin(60+45)

hence, we have sin105=sin(60+45)=sin60 x cos45+cos60 x sin45

= √3/2 . √2/2 +1/2 ,√2/2 =

1/4(√6 + √2)

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