How do you find two consecutive odd integers whose sum is 116?

We have to find the two consecutive odd integers whose sum is 116.

Solution

Let the first odd integer be x.

Then, the next consecutive integer is (x+2).

Given that the sum of the integers is 116.

Then, we will write:

x + (x+2)= 116

Now we will simplify and solve the equation.

= x+ x + 2 = 116

= 2x + 2 = 116

now we will solve for x.

Subtract 2 from both sides.

= 2x = 116-2 = 114

= 2x = 114

now we will divide by 2.

= x = 57

Then, the next consecutive integer is 57+2 = 59.

Then, the integers are: 57 and 59

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