# How do you integrate int 1/x^2dx?

We have to integrate $\frac{1}{x^{2}}dx$

### Solution

We can express $\frac{1}{x^{2}}$ as $x^{-2}$

By power rule of integration we know that

∫ an da= (an+1 / n + 1) +C

so $\frac{1}{x^{2}}dx$

= $-x^{-1}$

= $-\frac{1}{x} + C$

$\frac{1}{x^{2}}dx$ = $-\frac{1}{x} + C$