Question

How to solve $8x+4=3\left(x-1\right)+7$ ?

Answer 1

Compute the required value:

Given : $8x+4=3\left(x-1\right)+7$

$$\begin{gathered} \Rightarrow 8x+4=3x-3+7 \\ \Rightarrow 8x+4=3x+4 \end{gathered}$$

Subtracting both the sides by $4$,

$$\begin{gathered} \Rightarrow 8x=3x \\ \Rightarrow 8x-3x=0 \\ \Rightarrow 5x=0 \\ \Rightarrow x=0 \end{gathered}$$

Hence, the value of $x$ is $0$.