To calculate temperature we have to convert grams of S to moles of S then moles of H2S then use ideal gas law to find temperature
Given
Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid), unbalanced.
Also, 3.0 L of H2S gas at 760 torr produced 4.8 g of sulfur.
Find out
We need to find out the temperature in celsius.
Solution
Let us first write the balanced Chemical equation
\(2H_{2}S + SO_{2}\rightarrow 2H_{2}O + 3S\)Now will calculate the moles of H2S
Moles of H2S= \(4.8 g of S X \frac{1 mole of S}{32.06 g of S} X \frac{2 mole of H_{2}S}{3 mole of S}\)
Moles of H2S= 0.0998 Moles of H2S
From ideal gas law we know that
PV = nRT
P= \(760 Torr X \frac{1}{760 Torr} = 1 atm\)
T=PV / nR
T = \(\frac{1 atm X 3.o L}{o.o998 mol X 0.0826 L atm . K^{-1}mol^{-1}}\)
T = (366-273.15)
T= 90ºC
The temperature in celsius is 90º
