Question

Identify $"\mathrm{X}"$in the reaction $\underset{\mathrm{Hydrochloric}\mathrm{acid}}{2\mathrm{HCl}\left(\mathrm{l}\right)}+\underset{\mathrm{Copper}\mathrm{oxide}}{\mathrm{CuO}\left(\mathrm{s}\right)}\to \mathrm{X}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$

Answer 1

Acid and metallic oxide reaction:

1. When acid reacts with metallic oxide salt and water are formed.
2. Because metal oxides are basic in nature, they neutralize each other when an acid reacts with them. resulting in salt and water formation.
3. In the given reaction hydrochloric acid reacts with copper oxide to give salt of copper chloride and water. The balanced equation for the reaction is $\underset{\mathrm{Hydrochloric}\mathrm{acid}}{2\mathrm{HCl}\left(\mathrm{l}\right)}+\underset{\mathrm{Copperoxide}}{\mathrm{CuO}\left(\mathrm{s}\right)}\to \underset{\mathrm{Copper}\mathrm{chloride}}{{\mathrm{CuCl}}_2\left(\mathrm{s}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$
4. Because chlorine ions replace the oxygen in copper oxide, the oxygen joins with hydrogen atoms to generate water, this is a double displacement reaction.

Therefore, $\mathrm{X}={\mathrm{CuCl}}_2$ in the given reaction.