Question

Identify $\text{'}\mathrm{x}\text{'},\text{'}\mathrm{y}\text{'}$and $\text{'}\mathrm{z}\text{'}$in the following reaction $\underset{\mathrm{potassium}\mathrm{chlorate}}{{\mathrm{KClO}}_3\left(\mathrm{x}\right)}\stackrel{\left(\mathrm{y}\right)}{\to }\underset{\mathrm{Potassium}\mathrm{chloride}}{2\mathrm{KCl}\left(\mathrm{x}\right)}+\underset{\mathrm{oxygen}}{{\mathrm{O}}_2\left(\mathrm{z}\right)}$

• A. $\mathrm{x}=$gas, $\mathrm{y}=$reaction condition, $\mathrm{z}=$gas
• B. $\mathrm{x}=$solid $\mathrm{y}=$liquid $\mathrm{z}=$gas
• C. $\mathrm{x}=$number of moles of ${\mathrm{KClO}}_3$, $\mathrm{y}=$reaction condition, $\mathrm{z}=$number of molecules of oxygen
• D. $\mathrm{x}=$The physical state of ${\mathrm{KClO}}_3$ and $\mathrm{KCl}$, $\mathrm{y}=$reaction condition, $\mathrm{z}=$Physical state of ${\mathrm{O}}_2$

Answer 1

The correct option is D

$\mathrm{x}=$The physical state of ${\mathrm{KClO}}_3$ and $\mathrm{KCl}$, $\mathrm{y}=$reaction condition, $\mathrm{z}=$Physical state of ${\mathrm{O}}_2$

The explanation for the correct option:

Option D: $\mathrm{x}=$the physical state of ${\mathrm{KClO}}_3$ and$\mathrm{KCl}$, $\mathrm{y}=$reaction condition, the $\mathrm{z}=$physical state of ${\mathrm{O}}_2$

1. A decomposition reaction is a chemical reaction that produces two or more products from one source.
2. As the potassium chlorate molecule breaks down into potassium chloride and oxygen, it is a decomposition reaction. This reaction is endothermic because it requires heat to break down the molecule.
3. According to the reaction $\underset{\mathrm{Potassium}\mathrm{chlorate}}{{\mathrm{KClO}}_3\left(\mathrm{x}\right)}\stackrel{\left(\mathrm{y}\right)}{\to }\underset{\mathrm{Potassium}\mathrm{chloride}}{2\mathrm{KCl}\left(\mathrm{x}\right)}+\underset{\mathrm{Oxygen}}{{\mathrm{O}}_2\left(\mathrm{z}\right)}$ $\mathrm{x}=$the physical state of ${\mathrm{KClO}}_3$ and$\mathrm{KCl}$, $\mathrm{y}=$reaction condition, the $\mathrm{z}=$physical state of${\mathrm{O}}_2$.
4. Hence it is the correct option.

Therefore, $\mathrm{x}=$the physical state of ${\mathrm{KClO}}_3$ and $\mathrm{KCl}$, $\mathrm{y}=$reaction condition, and $\mathrm{z}=$physical state of ${\mathrm{O}}_2$