Question

If $1$ part of a red pigment requires $75\mathrm{mL}$ of base, how much red pigment should we mix with $1800\mathrm{mL}$ of base?

Answer 1

Finding the required quantity of red pigment:

The quantity of red pigment required is directly proportional to the quantity of the base

Let the parts of red pigment required for $1800\mathrm{mL}$ be $\mathrm{x}$

$1$ part of red pigment : $75\mathrm{mL}$ of base

$\mathrm{x}$ part of red pigment : $1800\mathrm{mL}$ of base

$\Rightarrow \frac{1}{75}=\frac{\mathrm{x}}{1800}$

$\Rightarrow \mathrm{x}=\frac{1800}{75}$

$\Rightarrow$ $\mathrm{x}=24$

Hence, $24$ parts of red pigment are required for $1800\mathrm{mL}$ of base.