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Question

If 9999=4, 8888=8, 1816=6, 1212=0, then, 1919=?


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Solution

Find the value of the required number following the pattern

The holes in a number count as one point each.

Then you multiply The number of unique numbers that have holes in them by the number of holes.

9999=4

Each 9 has one hole, so they are a total of 4 points

There is only one unique number 9 that scores points, so we multiply 1(4)=4

8888=8

Each 8 has two holes, so each 8 counts as two points, so we find their sum 2+2+2+2=8

There is only one unique number 8 that scores points, so we multiply 1(8)=8

1816=6

The 8 has two holes (2 points) and the 6 has one hole (1 point). Add those together (2+1=3). There are two unique numbers that score points, so multiply the sum by (2+1)×2=6

1212=0

Since, none of the numbers have holes in them.

Following the same rule,1919 has two holes(one hole in each 9) and there is one unique number, so 2×1=2.

Hence, 1919=2.


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