Question

If a letter of English alphabet is chosen at random then what is the probability that the letter is a consonant? -

Answer 1

English alphabets = 26 letters (5 vowels + 21 consonants)
Total number of outcomes = n(S) = 26
Let A be the event of choosing an English alphabet, which is a consonant.
A = {b, c, d, f, g, h, j, k, l, m, n, p, q, r, s t, v, w, x, y, z}
n(A) = 21
P(A) = n(A)/n(S) = 21/26
Hence, the required probability is 21/26.