If m times the mth term of an A.P. is equal to n times nth term, then (m+n)th term of the A.P is zero.
Explanation:
According to the nth term of an arithmetic progression, we have
tn = nth term of Ap = a + (n − 1)d … (1)
tm = mth term of AP = a + (m − 1)d … (2)
From, the given information, we can write
m × tm = n × tn
From (1) and (2), we can write
m[a + (m − 1)d] = n[a + (n − 1)d]
Now, simplify the equation, we get
m[a + (m − 1)d] − n[a + (n − 1)d] = 0
a(m − n) + d[(m + n)(m − n) − (m − n)] = 0
Now, take out the common terms, we get
(m − n)[a + d((m + n) − 1)] = 0
a + [(m + n) − 1]d = 0 … (3)
From equation (3), we can say
a + [(m + n) − 1]d = tm+n …. (4)
Now, comparing equations (3) and (4), we can conclude that
tm+n = 0.